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LeetCode Practice
  • Index
  • Array
    • 001 Max Consecutive Ones
    • 002 Find Numbers with Even Number of Digits
    • 003 Squares of a Sorted Array
    • 004 Duplicate Zeros
    • 005 Merge Sorted Array
    • 006 Remove Element
    • 007 Remove Duplicates from Sorted Array
    • 008 Check If N and Its Double Exist
    • 09 Valid Mountain Array
    • 10 Replace Elements with Greatest Element on Right Side
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  • Problem
  • Clarification:
  • Example 1:
  • Example 2:
  • Constraints:
  • Solution
  • Method 1 (Keep order)
  • Method 2 (Non-order)

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  1. Array

006 Remove Element

Previous005 Merge Sorted ArrayNext007 Remove Duplicates from Sorted Array

Last updated 4 years ago

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Problem

Given an array nums and a value val, remove all instances of that value and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array with O(1) extra memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Clarification:

Confused why the returned value is an integer but your answer is an array?

Note that the input array is passed in by reference, which means a modification to the input array will be known to the caller as well.

Internally you can think of this:

// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}

Example 1:

Input: nums = [3,2,2,3], val = 3
Output: 2, nums = [2,2]
Explanation: Your function should return length = 2, with the first two elements of nums being 2.
It doesn't matter what you leave beyond the returned length. For example if you return 2 with nums = [2,2,3,3] or nums = [2,2,0,0], your answer will be accepted.

Example 2:

Input: nums = [0,1,2,2,3,0,4,2], val = 2
Output: 5, nums = [0,1,4,0,3]
Explanation: Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4. Note that the order of those five elements can be arbitrary. It doesn't matter what values are set beyond the returned length.

Constraints:

  • 0 <= nums.length <= 100

  • 0 <= nums[i] <= 50

  • 0 <= val <= 100

Solution

Method 1 (Keep order)

Code

public class Solution {
    public int RemoveElement(int[] nums, int val) {
        int length = nums.Length;
        int index = length;
        
        while(index > 0){
            while(index > 0 && nums[index-1] == val){
                if(index !=length ){
                    for(int i= index-1; i < length-1; i++){
                        nums[i]= nums[i+1];
                    }
                }
                length--;
                index--;
            }
            index--;
        }
    return length;
    }
}

Idea

Method 2 (Non-order)

Code

public class Solution {
    public int RemoveElement(int[] nums, int val) {
        int length = nums.Length;
        int index=0;
        
        while(index < length){
            if(nums[index] == val){
                nums[index] = nums[length-1];
                length--;
            }
            else{
                index++;
            }
        }
        
    return length;
    }
}

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