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LeetCode Practice
  • Index
  • Array
    • 001 Max Consecutive Ones
    • 002 Find Numbers with Even Number of Digits
    • 003 Squares of a Sorted Array
    • 004 Duplicate Zeros
    • 005 Merge Sorted Array
    • 006 Remove Element
    • 007 Remove Duplicates from Sorted Array
    • 008 Check If N and Its Double Exist
    • 09 Valid Mountain Array
    • 10 Replace Elements with Greatest Element on Right Side
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  • Given a fixed length array arr of integers, duplicate each occurrence of zero, shifting the remaining elements to the right.
  • Example 1:
  • Example 2:
  • Note:
  • Solution

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  1. Array

004 Duplicate Zeros

Given a fixed length array arr of integers, duplicate each occurrence of zero, shifting the remaining elements to the right.

Note that elements beyond the length of the original array are not written.

Do the above modifications to the input array in place, do not return anything from your function.

Example 1:

Input: [1,0,2,3,0,4,5,0]
Output: null
Explanation: After calling your function, the input array is modified to: [1,0,0,2,3,0,0,4]

Example 2:

Input: [1,2,3]
Output: null
Explanation: After calling your function, the input array is modified to: [1,2,3]

Note:

  1. 1 <= arr.length <= 10000

  2. 0 <= arr[i] <= 9

Solution

public class Solution {    
    public void DuplicateZeros(int[] arr) {
        bool dupicate = false;    
        //Traverse array from left to right to find 0;
        for(int count = 0; count<arr.Length; count++){
            if(arr[count]==0){                    //Find a zero
                if(dupicate == false){            //This zero is not a duplicate
                 //shift all the elements from that index onwards one position to the right. 
                 //Set the element beside that index to zero.
                 for(int index=arr.Length-1; index>count; index--){
                  arr[index] = arr[index-1];
                  arr[count] = 0;
                  dupicate = true;
                } 
            }
            count++;
            dupicate = false;     
          } 
        }        
    }  
}
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Last updated 4 years ago

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